A 920 g empty iron kettle is put on a stove.How much heat in joules must it absorb to raise its temperature form 15.0ºC to 93.0ºC? (The specific heat for iron is 113 cal/kg · ºC. )
A)33,900 J
B)40,500 J
C)8110 J
D)40,100 J

Question

Quizplus · Accepted Answer

The correct answer is A.The heat required to raise the temperature of the kettle can be calculated using the formula:Q = mcΔTwhere:Q is the heat required (in joules)m is the mass of the kettle (in kilograms)c is the specific heat of iron (in joules per kilogram per degree Celsius)ΔT is the change in temperature (in degrees Celsius)Plugging in the given values, we get:Q = (0.920 kg)(113 J/kg · °C)(93.0 °C - 15.0 °C)Q = 33,900 JTherefore, the kettle must absorb 33,900 joules of heat to raise its temperature from 15.0 °C to 93.0 °C.

A 920 G Empty Iron Kettle Is Put on a Stove.How