A container with rigid walls is filled with 4 mol of air with C_v= 2.5R.How much does the internal energy change if the temperature rises from 16ºC to 437ºC? A)35,000 J B)421 J C)3500 J D)8750 J

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Quizplus · Accepted Answer

The internal energy change is given by:$$\Delta U = nC_v \Delta T$$where:* n is the number of moles of gas* C_v is the molar specific heat at constant volume* \Delta T is the change in temperatureSubstituting the given values into the equation, we get:$$\Delta U = (4 	ext{ mol})(2.5R)(437\degree	ext{C} - 16\degree	ext{C})$$$$\Delta U = (4 	ext{ mol})(2.5R)(421\degree	ext{C})$$$$\Delta U = 35,000 	ext{ J}$$Therefore, the correct answer is A.

A Container with Rigid Walls Is Filled with 4 Mol