A 1000.0 kg car experiences a net force of 9500 N while decelerating from 30.0 m/s to 23.4 m/s.How far does it travel while slowing down?
A)19 m
B)17 m
C)20 m
D)22 m

Question

Quizplus · Accepted Answer

Using the work-energy principle, the work done by the net force equals the change in kinetic energy. The initial kinetic energy is (1/2)*1000*(30)^2 and the final kinetic energy is (1/2)*1000*(23.4)^2. The work done is force times distance, so 9500*d = change in kinetic energy. Solving for d gives approximately 19 m.

A 10000 Kg Car Experiences a Net Force of 9500 N