A prankster drops a water balloon from the top of a building on an unsuspecting person on the sidewalk below.If the balloon is traveling at 30.3 m/s when it strikes a person's head (1.5 m above the ground),how tall is the building? Neglect air resistance.
A)48 m
B)47 m
C)50 m
D)51 m

Question

Quizplus · Accepted Answer

Using the kinematic equation $ v^2 = u^2 + 2as $, where $ v = 30.3 \, \text{m/s} $, $ u = 0 \, \text{m/s} $, $ a = 9.8 \, \text{m/s}^2 $, and $ s $ is the distance fallen. Solving for $ s $, we get $ s = \frac{v^2}{2a} = \frac{(30.3)^2}{2 \times 9.8} \approx 46.8 \, \text{m} $. Adding the 1.5 m height of the person, the building is approximately 48 m tall.

A Prankster Drops a Water Balloon from the Top of a Building