A ball is thrown straight up. Its height, in feet, at time t, in seconds, is represented by the equation $h ( t ) = 20 t - 16 t ^ { 2 } + 10$. Determine the maximum height of the ball. (Hint: Consider the velocity of the ball at the moment the ball reaches its maximum height.)Enter just a reduced fraction of form $\frac { a } { b }$ . No units.

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The Answer of A ball is thrown straight up. Its height, in feet, at time t, in seconds, is represented by the equation $h ( t ) = 20 t - 16 t ^ { 2 } + 10$. Determine the maximum height of the ball. (Hint: Consider the velocity of the ball at the moment the ball reaches its maximum height.)Enter just a reduced fraction of form $\frac { a } { b }$ . No units.

A Ball Is Thrown Straight Up h(t)=20t−16t2+10h ( t ) = 20 t - 16 t ^ { 2 } + 10h(t)=20t−16t2+10

A Ball Is Thrown Straight Up $h ( t ) = 20 t - 16 t ^ { 2 } + 10$