An automobile's brakes are applied at time t = 0 when the vehicle is traveling at 48 ft/sec. The brakes cause the automobile to decelerate so that after t sec the velocity is given by $\mathrm { v } ( \mathrm { t } ) = 48 - 16 \mathrm { t }$ How long will it take for the vehicle to come to a complete stop?
Enter just an integer, no units.

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The Answer of An automobile's brakes are applied at time t = 0 when the vehicle is traveling at 48 ft/sec. The brakes cause the automobile to decelerate so that after t sec the velocity is given by $\mathrm { v } ( \mathrm { t } ) = 48 - 16 \mathrm { t }$ How long will it take for the vehicle to come to a complete stop?
Enter just an integer, no units.

An Automobile's Brakes Are Applied at Time T = 0 v(t)=48−16t\mathrm { v } ( \mathrm { t } ) = 48 - 16 \mathrm { t }v(t)=48−16t

An Automobile's Brakes Are Applied at Time T = 0 $\mathrm { v } ( \mathrm { t } ) = 48 - 16 \mathrm { t }$