A package is dropped from a helicopter moving upward at 1.5 m/s. If it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was released if air resistance is negligible?
A) 810 m
B) 1000 m
C) 1200 m
D) 1500 m

Question

Quizplus · Accepted Answer

The initial velocity of the package is 1.5 m/s upward. Using the equation of motion: $ h = v_i t + \frac{1}{2} g t^2 $, where $ v_i = -1.5 $ m/s (since it's upward), $ g = 9.8 $ m/s², and $ t = 16 $ s, we find $ h = -1.5 \times 16 + \frac{1}{2} \times 9.8 \times 16^2 = 1000 $ m.

A Package Is Dropped from a Helicopter Moving Upward at 1.5