A ball is tied to the end of a cable of negligible mass. The ball is spun in a circle with a radius 2.00 m making 7.00 revolutions every 10.0 seconds. What is the magnitude of the acceleration of the ball? A) 67.9 m/s² B) 38.7 m/s² C) 29.3 m/s² D) 14.8 m/s² E) 74.2 m/s²

Question

Quizplus · Accepted Answer

The acceleration of the ball is given by the formula a = v^2/r, where v is the velocity of the ball and r is the radius of its circular path. We can find the velocity of the ball by multiplying the circumference of its circular path (2πr) by the number of revolutions it makes per second (7/10), so v = 2πr(7/10). Plugging in r = 2.00 m and simplifying, we get v = 8.80 m/s. Therefore, the acceleration is a = v^2/r = (8.80 m/s)^2/(2.00 m) = 38.7 m/s^2. The answer is B.

A Ball Is Tied to the End of a Cable