An electrical motor spins at a constant 2857.0 rev/min. If the armature radius is 2.685 cm, what is the acceleration of the outer edge of the armature? A) 2403 m/s² B) 844.4 m/s² C) 241,100 m/s² D) 84.40 m/s²

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Quizplus · Accepted Answer

The acceleration can be calculated using the formula for centripetal acceleration: a = ω²r. First, convert rev/min to rad/s: ω = 2857 rev/min * (2π rad/rev) * (1 min/60 s) = 299 rad/s. Then, a = (299 rad/s)² * 0.02685 m = 2403 m/s².

An Electrical Motor Spins at a Constant 2857