A spring stretches by 21.0 cm when a 135 N object is attached. What is the weight of a fish that would stretch the spring by 31 cm?
A) 199 N
B) 91.0 N
C) 145 N
D) 279 N

Question

Quizplus · Accepted Answer

The spring constant k can be calculated using Hooke's Law: F = kx. For the 135 N object, k = 135 N / 0.21 m = 642.86 N/m. For a 31 cm stretch, the force (weight of the fish) is F = kx = 642.86 N/m * 0.31 m = 199 N.

A Spring Stretches by 21