A -7.0-μC point charge has a positively charged object in an elliptical orbit around it. If the mass of the positively charged object is 1.0 kg and the distance varies from 5.0 mm to 20.0 mm between the charges, what is the maximum electric potential difference through which the positive object moves? (k = 1/4πε₀ = 8.99 × 10⁹ N ∙ m²/C²)

Question

Quizplus · Accepted Answer

The electric potential difference (ΔV) is calculated using the formula ΔV = k * q * (1/r1 - 1/r2), where q is the charge, r1 is the closest distance, and r2 is the farthest distance. Substituting the given values: ΔV = 8.99 × 10^9 * 7.0 × 10^-6 * (1/0.005 - 1/0.02) = 9.4 MV.

A -70-μC Point Charge Has a Positively Charged Object in an an Elliptical