A sphere with radius 2.0 mm carries +1.0 μC of charge distributed uniformly throughout its volume. What is the potential difference, VB - VA, between point B, which is 4.0 m from the center of the sphere, and point A, which is 9.0 m from the center of the sphere? (k = 1/4πε0 = 8.99 × 10⁹ N ∙ m²/C²)

Question

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The potential difference between two points outside a charged sphere is given by V = kQ(1/rA - 1/rB). Substituting the given values, VB - VA = (8.99 × 10^9)(1.0 × 10^-6)(1/4 - 1/9) = 1200 V.

A Sphere with Radius 2