A rectangular loop of wire measures 1.0 m by 1.0 cm. If a 7.0-A current flows through the wire, what is the magnitude of the magnetic force on the centermost 1.0-cm segment of the 1.0-m side of the loop? (μ0 = 4π × 10^-7T ∙ m/A) A) 9.8 × 10^-6N B) 7.8 × 10^-7N C) 9.8 × 10^-8 N D) 4.9 × 10^-6 N

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Quizplus · Accepted Answer

The magnetic force on a current-carrying wire is given by the equation F = ILB, where I is the current, L is the length of the wire, and B is the magnetic field. In this case, the current is 7.0 A, the length of the wire is 1.0 cm, and the magnetic field is 4π × 10^-7T ∙ m/A * 7.0 A = 2.8 × 10^-6T. Therefore, the magnetic force on the centermost 1.0-cm segment of the 1.0-m side of the loop is F = (7.0 A)(1.0 cm)(2.8 × 10^-6T) = 9.8 × 10^-6N.

A Rectangular Loop of Wire Measures 1