A circular loop of wire of radius 10 cm carries a current of 6.0 A. What is the magnitude of the magnetic field at the center of the loop? (μ0 = 4π × 10^-7 T ∙ m/A) A) 3.8 × 10^-5 T B) 3.8 × 10^-7 T C) 1.2 × 10^-5 T D) 1.2 × 10^-7 T E) 3.8 × 10^-8T

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Quizplus · Accepted Answer

The magnetic field at the center of a circular loop is given by B = (μ0 * I) / (2 * R). Substituting the given values: B = (4π × 10^-7 T ∙ m/A * 6.0 A) / (2 * 0.1 m) = 3.8 × 10^-5 T.

A Circular Loop of Wire of Radius 10 Cm Carries