A solenoid of length 18 cm consists of closely spaced coils of wire wrapped tightly around a wooden core. The magnetic field strength is 2.0 mT inside the solenoid near its center when a certain current flows through the coils. If the coils of the solenoid are now pulled apart slightly, stretching it to 21 cm without appreciably changing the size of the coils, what does the magnetic field become near the center of the solenoid when the same current flows through the coils? (μ₀ = 4π × 10^-7 T ∙ m/A) A) 1.7 mT B) 3.4 mT C) 0.85 mT D) 2.0 mT

Question

Quizplus · Accepted Answer

The magnetic field strength of a solenoid is directly proportional to the number of turns per unit length. When the solenoid is stretched, the number of turns per unit length decreases, so the magnetic field strength decreases. The new magnetic field strength can be calculated as:B = μ₀nIn = N/LL = 21 cm = 0.21 mB = (4π × 10^-7 T ∙ m/A)(N/0.21 m)(I)B = (1.89 × 10^-6 T/m)(N)(I)Since the number of turns N and the current I remain the same, the new magnetic field strength is:B = (1.89 × 10^-6 T/m)(N)(I) = 2.0 mTTherefore, the magnetic field strength near the center of the solenoid when the same current flows through the coils is 2.0 mT.

A Solenoid of Length 18 Cm Consists of Closely Spaced