A diatomic molecule is vibrating in its first excited quantum state above the ground state. In that excited state, its frequency is 2.0 × 1013 Hz. What is the energy of the molecule in this state? (h = 6.626 × 10-34 J ∙ s,
= 1.055 × 10-34 J ∙ s, 1 eV = 1.60 × 10-19 J
A) 0.041 eV
B) 0.083 eV
C) 0.12 eV
D) 0.15 eV
E) 0.17 eV
Correct Answer:
Verified
Q6: A certain molecule has 2.00 eV of
Q8: In a p-type semiconductor,a hole is
A) a
Q14: A vibrating diatomic molecule has vibrational quantum
Q16: The moment of inertia of a fluorine
Q16: Covalent bonding is due to
A) the sharing
Q17: When a certain diatomic molecule undergoes a
Q21: The Fermi energy of rubidium at a
Q22: Approximately how many states in the range
Q23: The energy gap between the valence and
Q23: If one metal has double the number
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents