The reaction ²H + ²H →? ³H + ¹H releases 4.03 MeV of energy. If 1.0 kg of deuterium were to go through this reaction, how much energy would be produced? (1 eV = 1.60 × 10^-19 J, mdeuterium = 2.012 u, 1 u = 931.5 MeV/c² = 1.6605 × 10^-27 kg)

Question

Quizplus · Accepted Answer

The reaction releases 4.03 MeV of energy per reaction. 1 kg of deuterium contains 6.022 × 10²⁶ atoms. Therefore, the total energy released is 4.03 MeV/reaction × 6.022 × 10²⁶ reactions = 2.42 × 10³⁰ MeV. Converting to joules, we get 2.42 × 10³⁰ MeV × 1.60 × 10^-13 J/MeV = 3.87 × 10¹⁷ J.

The Reaction 2H + 2H →? 3H + 1H Releases

The Reaction ²H + ²H →? ³H + ¹H Releases