A parallel plate capacitor of capacitance C₀ has plates of area A with separation d between them.When it is connected to a battery of voltage V₀,it has charge of magnitude Q₀on its plates.While it is connected to the battery,the space between the plates is filled with a material of dielectric constant 3.After the dielectric is added,the magnitude of the charge on the plates and the new capacitance are A) $\frac { 1 } { 3 }$ Q₀, $\frac { 1 } { 3 }$ C₀ B)Q₀, $\frac { 1 } { 3 }$ C₀ C)Q₀,C₀ D)3Q₀,C₀ E)3Q₀,3C₀

Question

Quizplus · Accepted Answer

When a dielectric is inserted, the capacitance increases by a factor equal to the dielectric constant. Therefore, the new capacitance is 3C₀. Since the capacitor is connected to a battery, the voltage remains constant, and the charge on the plates increases by the same factor as the capacitance, resulting in a charge of 3Q₀.

A Parallel Plate Capacitor of Capacitance C0 Has Plates of Area

A Parallel Plate Capacitor of Capacitance C₀ Has Plates of Area