The plates of a parallel plate capacitor of capacitance $C _ { 0 }$ are horizontal.Into the gap a slab of dielectric material with $K = 2$ is placed,filling the bottom half of the gap between the plates.What is the resulting new capacitance?
A) $\frac { 2 } { 5 } C _ { 0 }$
B) $\frac { 3 } { 4 } C _ { 0 }$
C) $4 C _ { 0 }$
D) $\frac { 5 } { 2 } C _ { 0 }$
E) $\frac { 4 } { 3 } C _ { 0 }$

Question

Quizplus · Accepted Answer

The capacitor can be considered as two capacitors in series: one with the dielectric and one without. The capacitance of the dielectric-filled part is $2C_0$ and the other is $C_0$. The equivalent capacitance is $\frac{1}{C} = \frac{1}{2C_0} + \frac{1}{C_0}$, which simplifies to $\frac{4}{3}C_0$.

The Plates of a Parallel Plate Capacitor of Capacitance C0C _ { 0 }C0​

The Plates of a Parallel Plate Capacitor of Capacitance $C _ { 0 }$