Write the equation of a wave,traveling along the +x axis with an amplitude of 0.02 m,a frequency of 440 Hz,and a speed of 330 m/sec.
A)y = 0.02 sin [880 $\pi$(x/330 - t)]
B)y = 0.02 cos [880 $\pi$ x/330 -440t]
C)y = 0.02 sin [880 $\pi$(x/330 + t)]
D)y = 0.02 sin [2 $\pi$(x/330 + 440t)]
E)y = 0.02 cos [2 $\pi$(x/330 + 440t)]

Question

Quizplus · Accepted Answer

The correct equation for a wave traveling along the +x axis with an amplitude of 0.02 m, a frequency of 440 Hz, and a speed of 330 m/sec is:y = 0.02 sin [2π(440 Hz)(x/330 m/sec - t)]This equation is in the form y = A sin(2πft - kx), where A is the amplitude, f is the frequency, t is the time, k is the wavenumber, and x is the position. The amplitude is 0.02 m, the frequency is 440 Hz, the speed is 330 m/sec, and the wavenumber is 2π(440 Hz)/330 m/sec = 880π/330 m^-1. Substituting these values into the equation gives:y = 0.02 sin [880π/330 m^-1(x/330 m/sec - t)]

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