The equation $y = A \sin \left( k x - ? t + \frac { \pi } { 2 } \right)$ is the same as
A) $y = - A \sin \left( k x - \omega t + \frac { \pi } { 2 } \right)$
B) $y = A \cos ( k x - ? t )$
C) $y = - A \cos ( k x - \omega t )$
D) $y = - A \sin \left( k x - \omega t - \frac { \pi } { 2 } \right)$
E) $y = A \sin \left( k x - \omega t + \frac { 3 \pi } { 2 } \right)$

Question

Quizplus · Accepted Answer

The given equation $y = A \sin \left( k x - \omega t + \frac{\pi}{2} \right)$ can be rewritten using the identity $\sin(\theta + \frac{\pi}{2}) = \cos(\theta)$, which simplifies to $y = A \cos(kx - \omega t)$.

The Equation y=Asin⁡(kx−?t+π2)y = A \sin \left( k x - ? t + \frac { \pi } { 2 } \right)y=Asin(kx−?t+2π​)

The Equation $y = A \sin \left( k x - ? t + \frac { \pi } { 2 } \right)$