What is the structure of the compound in the following ¹H-NMR spectrum with the molecular formula C₄H₇Br? Relative integration is shown.

Question

Quizplus · Accepted Answer

The ^{1 peak at 1.6 ppm with integration of 3 corresponds to a typical methyl group (-CH3). The} peak at 7.2 ppm with integration of 1 corresponds to a single aromatic proton. The _{4 peak at 7.4 ppm with integration of 2 corresponds to two protons attached to an unsaturated carbon. The}H peak at 7.6 ppm with integration of 1 corresponds to a proton attached to a hydrogen on an unsaturated carbon. The _{7 peak at 7.8 ppm with integration of 1 corresponds to a proton attached to a hydrogen on an unsaturated carbon. Finally, the}Br peak at around 6 ppm with integration of 1 corresponds to a proton attached to a bromine atom. This indicates a compound with a structure of an aromatic ring with an attached methyl group plus two unsaturated carbons with one hydrogen on each and a bromine atom. The correct choice is therefore C, which is the only answer that matches this structure.

What Is the Structure of the Compound in the Following