What is the structure of the compound in the following ¹H-NMR spectrum with the molecular formula C₅H₁₀O? The IR spectrum does not show any characteristic stretches around 1700 cm^-1.Relative integration is shown.

Question

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1. The molecular formula is C₅H₁₀O, which indicates the presence of carbon, hydrogen, sulfur, and oxygen. 2. The H-NMR spectrum shows six signals, which indicates that there are six different types of protons in the molecule. 3. The signal at 2.0 ppm with an integration of 3 corresponds to the methyl group (-CH3) attached to a sulfur atom. 4. The signal at 2.8 ppm with an integration of 6 corresponds to the methylene group (-CH2-) attached to a sulfur atom. 5. The signal at 4.1 ppm with an integration of 2 corresponds to the methine group (-CH-) attached to a sulfur atom. 6. The signal at 7.3 ppm with an integration of 1 corresponds to the proton attached to the benzene ring. 7. The absence of any characteristic stretches around 1700 cm^-1 in the IR spectrum suggests the absence of a carbonyl group (C=O), which rules out the possibility of the molecule containing a ketone, aldehyde, or carboxylic acid functional group. 8. The presence of a benzene ring is indicated by the chemical shift of the aromatic proton at 7.3 ppm. 9. Based on the above observations, the most likely structure of the compound is as shown in choice A, which contains a benzene ring attached to a sulfur atom and multiple sulfur-containing side chains.

What Is the Structure of the Compound in the Following