A compound has the molecular formula,C₆H₁₂O₂.Its IR spectrum shows a strong absorption band near 1740 cm^-1;its ¹H NMR spectrum consists of two singlets,at $\delta$1.2 and $\delta$3.6.The most likely structure for this compound is:

Question

Quizplus · Accepted Answer

Firstly, the molecular formula shows that the compound has 1 carbon, 1 hydrogen, 16 boron, 1 sulfur, 112 hydrogen, and 12 oxygen atoms. This indicates a highly boron-rich environment, which is consistent with option E.
Secondly, the strong absorption near 1740 cm-1 in the IR spectrum suggests the presence of a carbonyl group (C=O), which is present in structures III, IV, and V.
Finally, the two singlets at 1.2 and 3.6 ppm in the 1H NMR spectrum are consistent with the presence of two different types of protons, probably CH3 and CH groups. Option E is the only structure that satisfies all of these criteria, with the carbonyl group located at the end of the 6-membered ring and the CH and CH3 groups located on the side chain.

A Compound Has the Molecular Formula,C6H12O2 δ\deltaδ 12 And Has δ\deltaδ 36The Most Likely Structure for This Compound Is: A)

A Compound Has the Molecular Formula,C₆H₁₂O₂ $\delta$ 12 And Has $\delta$ 36The Most Likely Structure for This Compound Is:
A)