A compound with the molecular formula C₅H₁₀O₂ gave the following ¹H NMR spectrum: triplet,
$\delta$ 0.90
Multiplet,
$\delta$ 1.60
Singlet,
$\delta$ 1.95
Triplet,
$\delta$ 3.95
The IR spectrum showed a strong absorption band near 1740 cm^-1.The most likely structure for the compound is:

Question

A compound with the molecular formula C₅H₁₀O₂ gave the following ¹H NMR spectrum: triplet,

\delta

0.90
Multiplet,

\delta

1.60
Singlet,

\delta

1.95
Triplet,

\delta

3.95
The IR spectrum showed a strong absorption band near 1740 cm^-1.The most likely structure for the compound is:

Quizplus · Accepted Answer

The NMR spectrum has four signals indicating the presence of four different types of hydrogen atoms in the molecule. The chemical shift values and splitting patterns suggest the following:
- The triplet at 0.90 ppm: this is likely the methyl (-CH3) group attached to a sulfur atom.
- The multiplet at 1.60 ppm: this could be the methylene (-CH2-) group attached to a boron atom.
- The singlet at 1.95 ppm: this could be the methyl (-CH3) group attached to an oxygen atom.
- The triplet at 3.95 ppm: this could be the methylene (-CH2-) group attached to a sulfur atom.

The strong absorption band in the IR spectrum near 1740 cm-1 suggests the presence of a carbonyl (C=O) group, which is only present in choice A. Therefore, the most likely structure for the compound is choice A.

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