Why is this sequence,CH₂=CHCH₂OH + HBr,then CrO₃/H₂SO₄/H₂O,finally xs NH₃,not a good method for the preparation of L-alanine?

Question

Quizplus · Accepted Answer

The given synthesis pathway starts with the addition of HBr to a substituted alkene, which produces a racemic mixture of the intermediate. As a result, the final product will also be racemic, containing equal amounts of L-alanine and its enantiomer D-alanine. Therefore, this method is not suitable for the preparation of L-alanine as it would require a separate step for enantiomer separation. A better method would involve the use of chiral starting materials or chiral catalysts to ensure the formation of a single enantiomer.

Why Is This Sequence,CH2=CHCH2OH + HBr,then CrO3/H2SO4/H2O,finally Xs NH3,not a Good

Why Is This Sequence,CH₂=CHCH₂OH + HBr,then CrO₃/H₂SO₄/H₂O,finally Xs NH₃,not a Good