The position vector of an object is given by and 4 s later,its position vector is .The units are in m.The magnitude of the change in the position vector is
A)0 m
B) m
C) m
D)10 m
E) m

Question

The position vector of an object is given by  and 4 s later,its position vector is  .The units are in m.The magnitude of the change in the position vector  is
A)0 m 
B) m 
C) m 
D)10 m 
E) m

Quizplus · Accepted Answer

To find the magnitude of the change in position vector, we need to subtract the final position vector from the initial position vector:

11eaa331_f505_469f_9fad_cd6bfcddc647_TB6079_11 - 11eaa331_f505_469e_9fad_93ced3241962_TB6079_11

= 11eaa331_f505_46a0_9fad_1b07d725bb50_TB6079_11

The magnitude of the change in position vector is the absolute value of this vector, which is:

|11eaa331_f505_46a0_9fad_1b07d725bb50_TB6079_11|

Using the distance formula, we get:

sqrt((11^2) + (0^2) + (1^2)) = sqrt(122)

Therefore, the answer is C) 11eaa331_f505_46a2_9fad_ab68167d437d_TB6079_11 m.

The Position Vector of an Object Is Given by