A hoop of radius 3.05 n has a mass of 145 kg.Its moment of inertia is mR².The hoop rolls without slipping along a horizontal plane.If the center of mass of the hoop has a speed of 0.305 m/s,the work required to bring the hoop to rest is A)6.78 J B)13.5 J C)682 J D)217 J E)4.34 kJ

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Quizplus · Accepted Answer

The work required to bring the hoop to rest is equal to its total kinetic energy, which includes both translational and rotational kinetic energy. The translational kinetic energy is (1/2)mv^2 and the rotational kinetic energy is (1/2)Iω^2. For a hoop, I = mR^2 and ω = v/R. Substituting these into the equations and adding them gives the total kinetic energy, which is 13.5 J.

A Hoop of Radius 3