A horizontal pipe of 30 cm² cross-sectional area carries water at a speed of 2.5 m/s.This pipe feeds a smaller pipe of cross section 10 cm².Find the speed of water flow in the smaller pipe. A)3.5 m/s B)0.8 m/s C)2.5 m/s D)7.5 m/s E)23 m/s

Question

Quizplus · Accepted Answer

The speed of water flow in the smaller pipe can be found using the principle of conservation of mass, which implies that the flow rate (volume per time) must be constant throughout the system. The flow rate in the first pipe is the product of its cross-sectional area and the speed of water, which is $30 \, \text{cm}^2 \times 2.5 \, \text{m/s}$. To find the speed in the smaller pipe, we use the formula $\text{Area}_1 \times \text{Speed}_1 = \text{Area}_2 \times \text{Speed}_2$. Substituting the given values, $30 \times 2.5 = 10 \times \text{Speed}_2$, solving for $\text{Speed}_2$ gives $7.5 \, \text{m/s}$.

A Horizontal Pipe of 30 Cm2 Cross-Sectional Area Carries Water

A Horizontal Pipe of 30 Cm² Cross-Sectional Area Carries Water