A wave on a string has a frequency of 100 Hz and travels at a speed of 24 m/s.The minimum distance between two points with a phase difference of 60º is
A)0.040 m
B)0.12 m
C)0.14 m
D)0.24 m
E)25 m

Question

Quizplus · Accepted Answer

The phase difference of 60º corresponds to 1/6 of a wave cycle since 360º represents a full cycle. The wavelength ($\lambda$) can be found using the wave speed ($v$) and frequency ($f$) formula: $\lambda = v / f = 24 \, \text{m/s} / 100 \, \text{Hz} = 0.24 \, \text{m}$. Therefore, 1/6 of this wavelength is $0.24 \, \text{m} / 6 = 0.04 \, \text{m}$, which is the minimum distance between two points with a phase difference of 60º.

A Wave on a String Has a Frequency of 100