Two sound waves,one wave is given by y₁ = p_o sin (kx - $\omega$t)and the other by y₂ = p_o sin (kx - $\omega$t + $\pi$/4).The phase constant resulting from the interference of the two waves is A)$\pi$/8 B)$\pi$/4 C)$\pi$/2 D)$\pi$ E)0

Question

Quizplus · Accepted Answer

The phase constant for the resulting wave is the average of the phase constants of the two individual waves. The phase constant for the first wave is 0, and the phase constant for the second wave is π/4. Therefore, the phase constant for the resulting wave is (0 + π/4)/2 = π/8.

Two Sound Waves,one Wave Is Given by Y1 = Po ω\omegaω

Two Sound Waves,one Wave Is Given by Y₁ = P_o $\omega$