An ideal gas whose original temperature and volume are 27ºC and 0.283 m³ undergoes an isobaric expansion.If the final temperature is 87ºC,then the final volume is approximately A)0.0340 m³ B)0.0552 m³ C)0.170 m³ D)0.340 m³ E)1.45 m³

Question

Quizplus · Accepted Answer

For an isobaric process, the final volume can be calculated using the formula $V_f = V_i \times \frac{T_f}{T_i}$, where $T$ is in Kelvin. Converting the temperatures to Kelvin gives $T_i = 300K$ and $T_f = 360K$. Thus, $V_f = 0.283 \times \frac{360}{300} = 0.3396 \, m^3$, which is approximately $0.340 \, m^3$.

An Ideal Gas Whose Original Temperature and Volume Are 27ºC