A 1 L container contains O₂ gas at STP.If the diameter of the O₂ molecule is 3.75 $\times$ 10 ¹⁰m,the mean free path of the O₂ molecule is A)5.96 $\times$ 10 ^-8 m B)6.53$\times$10 ^-8 m C)4.57 $\times$ 10 ^-8 m D)6.89 $\times$ 10 ^-8 m E)7.67 $\times$ 10 ^-8 m

Question

Quizplus · Accepted Answer

We can use the mean free path formula:

mean free path = (1/√2) * (volume of the container)/(π * (diameter of molecule)^2 * number of molecules)

Plugging in the values, we get:

mean free path = (1/√2) * (1 L)/(π * (3.75 x 10^-10 m)^2 * (6.022 x 10^23 molecules/mol))

mean free path = 5.96 x 10^-8 m

Therefore, the best choice is (A).

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