A small lake has a surface area of 10000 m².Assuming that the average depth of the lake is 2 m,how much heat is released when the average temperature of the water in the lake drops by 1C $\circ$ ? A)8.36 $\times$ 10¹⁰ J B)8.36 $\times$ 10⁷ J C)2.0 $\times$ 10⁸ J D)2.0 $\times$ 10¹¹ J E)8.36 $\times$ 10³ J

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Quizplus · Accepted Answer

The heat released can be calculated using the formula Q = mcΔT, where m is the mass of the water, c is the specific heat capacity of water (approximately 4.186 J/g°C), and ΔT is the change in temperature. The volume of the lake is 10000 m^2 * 2 m = 20000 m^3. Since the density of water is approximately 1000 kg/m^3, the mass of the water is 20000 m^3 * 1000 kg/m^3 = 20,000,000 kg. The heat released for a 1°C drop is therefore Q = 20,000,000 kg * 4.186 J/g°C * 1°C = 8.372 * 10^10 J, which is approximately 8.36 * 10^10 J.

A Small Lake Has a Surface Area of 10000 M2 ∘\circ∘

A Small Lake Has a Surface Area of 10000 M² $\circ$