If 100 g of steam at 100 $\circ$ C were mixed with 10 kg of ice at -100 $\circ$ C,find the final temperature of the mixture assuming no heat losses to the surroundings.
A)-85 $\circ$ C
B)-65 $\circ$ C
C)0 $\circ$ C
D)-15 $\circ$ C
E)-43 $\circ$ C

Question

Quizplus · Accepted Answer

Explanation:The heat lost by the steam is equal to the heat gained by the ice.Q = mL = 100 g * 540 cal/g = 54,000 calQ = mc(t - 0) = 10 kg * 0.5 cal/g * t = 5000t cal54,000 = 5000tt = 10.8 C

If 100 G of Steam at 100 ∘\circ∘ C Were Mixed with 10 Kg of Ice at -100

If 100 G of Steam at 100^$\circ$C Were Mixed with 10 Kg of Ice at -100