Use the following to answer the question:
-An ideal gas initially at 50ºC and pressure P₁ = 250 kPa occupies a volume V₁ = 4.5 L.It undergoes a quasistatic,isothermal expansion until its pressure is reduced to 150 kPa.How much work was done by the gas during this process? R = 8.314 J/mol·K = 8.206 L·atm/mol·K.

Question

Use the following to answer the question:

-An ideal gas initially at 50ºC and pressure P₁ = 250 kPa occupies a volume V₁ = 4.5 L.It undergoes a quasistatic,isothermal expansion until its pressure is reduced to 150 kPa.How much work was done by the gas during this process? R = 8.314 J/mol·K = 8.206 L·atm/mol·K.

Quizplus · Accepted Answer

We can use the formula for work done by a gas during an isothermal process:
W = nRT ln (P1/P2)
where n is the number of moles of gas, R is the gas constant, T is the temperature in Kelvin, and P1 and P2 are the initial and final pressures, respectively.

First, we need to find the number of moles of gas using the ideal gas law:
PV = nRT
n = PV/RT

n = (250 kPa x 4.5 L) / (8.206 L·atm/mol·K x (50 + 273) K)
n = 0.0461 mol

Now, we can plug in the values for W:
W = nRT ln (P1/P2)
W = (0.0461 mol)(8.314 J/mol·K)(323 K) ln (250 kPa/150 kPa)
W = 575 J

Therefore, the answer is C.

Use the Following to Answer the Question