A car of mass 2000 kg is traveling at 22.0 m/s on a day when the temperature is 20.0ºC.The driver steps on the brakes and stops the car.By how much does the entropy of the universe increase?

Question

Quizplus · Accepted Answer

The entropy of the universe increases due to the conversion of the car's kinetic energy into heat and its subsequent dissipation into the environment. The change in entropy ($\Delta S$) can be calculated using the formula $\Delta S = \frac{Q}{T}$, where $Q$ is the heat generated (equal to the kinetic energy lost by the car) and $T$ is the absolute temperature in Kelvin.First, convert the temperature from Celsius to Kelvin: $T = 20.0ºC + 273.15 = 293.15 K$.Calculate the kinetic energy ($KE$) lost by the car: $KE = \frac{1}{2}mv^2 = \frac{1}{2} \times 2000 \times (22.0)^2 = 484000 J$ or $484 kJ$.Then, calculate the change in entropy: $\Delta S = \frac{Q}{T} = \frac{484 kJ}{293.15 K} \approx 1.65 kJ/K$.The closest answer is 1.6 kJ/K.

A Car of Mass 2000 Kg Is Traveling at 22 ×\times×

A Car of Mass 2000 Kg Is Traveling at 22 $\times$