The magnetic field at a distance of 50 cm from a long,straight wire carrying a current of 5.0 A is approximately
A)10 $\mu$T
B)50 $\mu$T
C)5.0 $\mu$T
D)32 $\mu$T
E)2.0 $\mu$T

Question

Quizplus · Accepted Answer

The magnetic field around a long, straight wire carrying current is given by:

B = (μ₀/4π) * (I/r)

Where:
μ₀ = 4π × 10^-7 T m/A is the permeability of free space
I = 5.0 A is the current in the wire
r = 50 cm = 0.5 m is the distance from the wire.

Plugging in the values, we get:

B = (μ₀/4π) * (I/r)
B = (4π × 10^-7 T m/A / 4π) * (5.0 A / 0.5 m)
B = (10^-7 T m/A) * 10 T
B = 1.0 × 10^-6 T = 1.0 μT

So the magnetic field at a distance of 50 cm from the wire is approximately 2.0 μT, which corresponds to choice E.

The Magnetic Field at a Distance of 50 Cm from a Long,straight