The force per unit length between two current-carrying wires is expressed as where I is the current,d the separation of the wires,and l the length of each wire.A plot of force per unit length versus I² gives a straight line,the slope of which is A)$\mu$₀ B)F/l C)(2$\pi$d/$\mu$₀)^1/2 D)$\mu$₀/2$\pi$d E)FI²/l

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The given expression for force per unit length is: F/l = (𝑚𝑚0I^2/l) * d where 𝑚𝑚0 is magnetic constant and I is current through each wire. On plotting F/l vs I, we get a straight line with slope (𝑚𝑚0I^2/l) * d. Comparing this with the given equation, we get: 𝑚𝑚0I^2/4𝜋d * l = 11𝜇₀/2 (where 𝜇₀ is permeability of free space) Therefore, the slope of the line is: 𝑚𝑚0I^2/l * d = (22𝜇₀/4𝜋d) * l = F/(2ld) = F1F1F1S1μF1F1F10₀/2F1F1F1S1πF1F1F10d

The Force Per Unit Length Between Two Current-Carrying Wires Is μ\muμ

The Force Per Unit Length Between Two Current-Carrying Wires Is $\mu$