Two long,parallel wires are spaced 1 m apart in air,and you have established a current of 1 A in each.The force per unit length that each wire exerts on the other is A)4$\pi\mu$₀ B)2$\pi\mu$₀ C)$\mu$₀ D)$\mu$₀/4$\pi$ E)$\mu$₀/2$\pi$

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The force per unit length between two long, parallel wires is given by:$$F = \frac{\mu_0 I_1 I_2}{2\pi d}$$where:* F is the force per unit length* $\mu_0$ is the permeability of free space* $I_1$ and $I_2$ are the currents in the wires* d is the distance between the wiresIn this case, we have $I_1 = I_2 = 1 A$ and $d = 1 m$. Therefore, the force per unit length is:$$F = \frac{4\pi 	imes 10^{-7} T \cdot m/A^2 	imes 1 A 	imes 1 A}{2\pi 	imes 1 m} = 2 	imes 10^{-7} N/m$$

Two Long,parallel Wires Are Spaced 1 M Apart in Air,and πμ\pi\muπμ

Two Long,parallel Wires Are Spaced 1 M Apart in Air,and $\pi\mu$