Nickel has a density of 8.70 g/cm³ and a molecular mass of 58.7 g/mol.Its magnetic moment is 0.587 Bohr magnetons (1 Bohr magneton = 9.27 $\times$ 10^-24 A · m²).What is its saturation magnetization? A)4.85 $\times$ 10⁹ A/m B)8.92 $\times$ 10⁵ A/m C)9.27 $\times$ 10^-24 A/m D)8.92 $\times$ 10²⁸ A/m E)4.85 $\times$ 10⁵ A/m

Question

Quizplus · Accepted Answer

Saturation magnetization can be calculated using the formula: $M_s = \frac{n \mu}{V}$, where $n$ is the number of magnetic moments per unit volume, $\mu$ is the magnetic moment, and $V$ is the volume. Given the density ($\rho$) of nickel is 8.70 g/cm³ and its molar mass (M) is 58.7 g/mol, the number of moles per cm³ can be calculated as $n = \frac{\rho}{M}$. Each mole of nickel contributes a magnetic moment of 0.587 Bohr magnetons, which in units of A·m² is $0.587 \times 9.27 \times 10^{-24}$ A·m². The saturation magnetization ($M_s$) is then calculated by multiplying the number of magnetic moments per unit volume by the magnetic moment per atom, leading to the correct answer after performing the calculations.

Nickel Has a Density of 8 ×\times× 10-24 a · M2) ×\times×

Nickel Has a Density of 8 $\times$ 10^-24 a · M²) $\times$