If m = m_B in a paramagnetic material (m_B = 9.27 $\times$ 10^-24 J/T),at what temperature is the magnetization 3% of the saturation magnetization in an applied magnetic field of 1.00 T? A)12.8 K B)7.46 K C)22.4 K D)67.2 K E)3.73 K

Question

Quizplus · Accepted Answer

We can use the Curie Law equation to solve for the temperature (T) at which the magnetization (m) is 3% of the saturation magnetization (mS) in an applied magnetic field (B) of 1.00 T:

m = (mS/3) * (x/T)

where x is a constant equal to 1.38 x 10^-23 J/K (Boltzmann's constant).

Rearranging the equation and plugging in the given values, we get:

T = (mS/3) * (x/m) = (9.27 x 10^-24 J/T) / (3/100) * (1.38 x 10^-23 J/K / 1.00 T)

T ≈ 7.46 K

Therefore, the answer is B.

If M = MB in a Paramagnetic Material (MB = ×\times×

If M = M_B in a Paramagnetic Material (M_B = $\times$