You connect a 250-$\Omega$ resistor,a 1.20-mH inductor,and a 1.80-$\mu$F capacitor in series across a 60.0-Hz,120-V (peak)source.The resonant frequency of your circuit is approximately
A)56.9 Hz
B)80.5 kHz
C)3.42 kHz
D)37.8 kHz
E)165 Hz

Question

Quizplus · Accepted Answer

The resonant frequency of an RLC circuit can be calculated using the following formula:
fres = 1 / (2π√(LC))

Given:
R = 250 Ω
L = 1.20 mH = 1.20 x 10^-3 H
C = 1.80 μF = 1.80 x 10^-6 F
f = 60 Hz

Using the formula for resonant frequency:
fres = 1 / (2π√(LC))
fres = 1 / (2π√(1.2 x 10^-3 x 1.8 x 10^-6))
fres = 3.42 kHz

Therefore, the resonant frequency of the circuit is 3.42 kHz, which is closest to option C (3.42 kHz).

You Connect a 250- Ω\OmegaΩ Resistor,a 1 μ\muμ F Capacitor in Series Across a 60

You Connect a 250- $\Omega$ Resistor,a 1 $\mu$ F Capacitor in Series Across a 60