A series RLC circuit with L = 5 H,C = 10 µF,and R = 10 $\Omega$ is driven by a generator with a maximum EMF of 100 V and a variable frequency.The Q value of this circuit is
A)24.6
B)47.3
C)64.5
D)70.7
E)100

Question

Quizplus · Accepted Answer

The Q factor (quality factor) of an RLC circuit is given by the formula $Q = \frac{1}{R} \sqrt{\frac{L}{C}}$. Plugging in the given values: $L = 5 \, \text{H}$, $C = 10 \, \mu\text{F} = 10 \times 10^{-6} \, \text{F}$, and $R = 10 \, \Omega$, we get $Q = \frac{1}{10} \sqrt{\frac{5}{10 \times 10^{-6}}} = \frac{1}{10} \sqrt{500000} = \frac{1}{10} \times 707.1 = 70.71$. Therefore, the closest value given is 70.7.

A Series RLC Circuit with L = 5 H,C = Ω\OmegaΩ

A Series RLC Circuit with L = 5 H,C = $\Omega$