Use the following figure for the next problem.
An AC power supply, V = 20 V sin where = 200 rad/s is connect to an inductor L = 180 mH and a capacitor C = 25 XL = 36 ohms, XC = 200 ohms, Z = 43.9 ohms
-What is the peak current flow through the inductor?
A)0.56 A
B)0.46 A
C)0.10 A
D)85 mA
E)None of these is correct.

Question

Use the following figure for the next problem. 
An AC power supply, V = 20 V sin  where  = 200 rad/s is connect to an inductor L = 180 mH and a capacitor C = 25  XL = 36 ohms, XC = 200 ohms, Z = 43.9 ohms
-What is the peak current flow through the inductor?
A)0.56 A 
B)0.46 A 
C)0.10 A 
D)85 mA 
E)None of these is correct.

Quizplus · Accepted Answer

The peak current flow through the inductor is 0.56 A. This is because the inductor opposes changes in current, so the current will initially be zero when the switch is closed. As the current increases, the inductor will store energy in its magnetic field. The peak current will be reached when the energy stored in the magnetic field is equal to the energy stored in the capacitor.

Use the Following Figure for the Next Problem