Light of wavelength 500 nm illuminates parallel slits and produces an interference pattern on a screen that is 1 m from the slits.In terms of the initial intensity I₀,the light's intensity in the interference pattern at a point for which the path difference is 300 nm is A)0.262 I₀ B)0.382 I₀ C)0.447 I₀ D)0.581 I₀ E)0.629 I₀

Question

Quizplus · Accepted Answer

The intensity at a point in an interference pattern is given by I = I₀ cos²(πΔx/λ), where Δx is the path difference and λ is the wavelength. For Δx = 300 nm and λ = 500 nm, I = I₀ cos²(π(300/500)) = I₀ cos²(0.6π) ≈ 0.382 I₀.

Light of Wavelength 500 Nm Illuminates Parallel Slits and Produces