In a double slit experiment,a very thin plate of glass of refractive index 1.58 is placed in the light path of one of the slit beams.When this was done,the center of the fringe pattern was displaced by 35 fringe widths.Calculate the thickness of the glass plate if the wavelength of light is 680 nm. A)4.1 $\times$ 10^-5 m B)1.5 $\times$ 10^-5 m C)3.0 $\times$ 10^-5 m D)8.2 $\times$ 10^-5 m E)3.8 $\times$ 10^-5 m

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The thickness of the glass plate can be calculated using the formula:t = (mλ)/(n-1)where:t is the thickness of the glass platem is the number of fringe widths displacedλ is the wavelength of lightn is the refractive index of the glass plateSubstituting the given values into the formula, we get:t = (35 x 680 nm)/(1.58-1) = 4.1 x 10^-5 mTherefore, the thickness of the glass plate is 4.1 x 10^-5 m.

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