What is the momentum (in SI units)of a photon of wavelength $\lambda$= 410 nm? (Planck's constant h = 6.626 $\times$ 10^-34 J·s) A)1.62 $\times$ 10^-27 kg m/s B)2.45 $\times$ 10^-27 kg m/s C)3.23 $\times$ 10^-27 kg m/s D)4.67 $\times$ 10^-27 kg m/s E)5.29 $\times$ 10^-27 kg m/s

Question

Quizplus · Accepted Answer

The momentum of a photon can be calculated using the following formula:

p = h/λ

Where p is the momentum, h is Planck's constant (6.626 × 10^-34 J·s), and λ is the wavelength of the photon.

Substituting the given values, we get:

p = (6.626 × 10^-34 J·s) / (410 × 10^-9 m)
  = 1.62 × 10^-27 kg m/s

Therefore, the momentum of the photon is 1.62 × 10^-27 kg m/s, which is option A.

What Is the Momentum (In SI Units)of a Photon of Wavelength