Calculate the photon energy for light of wavelength 600 nm.(Planck's constant h = 6.626 $\times$ 10^-34 J·s) A)1.24 eV B)1.98 eV C)2.07 eV D)2.48 eV E)2.98 eV

Question

Quizplus · Accepted Answer

The formula for photon energy is:
E = hc/λ
where E is energy, h is Planck's constant, c is the speed of light, and λ is the wavelength.
Substituting the given values, we get:
E = (6.626 x 10^-34 J·s) x (3.00 x 10^8 m/s) / (600 x 10^-9 m)
E = 3.31 x 10^-19 J
Converting to electron volts (eV):
E = 3.31 x 10^-19 J / 1.60 x 10^-19 J/eV
E = 2.07 eV
Therefore, the correct answer is (C) 2.07 eV.

Calculate the Photon Energy for Light of Wavelength 600 Nm ×\times×

Calculate the Photon Energy for Light of Wavelength 600 Nm $\times$