Suppose an electron is confined in a one-dimensional box of width L which is two times the Bohr's radius of 0.0529 nm.The energy of the ground state of the electron is A)5.38 $\times$ 10^-1⁸ J B)2.72 $\times$ 10^-1⁸ J C)1.36 $\times$ 10^-1⁸ J D)1.09 $\times$ 10^-18 J E)None of these is correct.

Question

Quizplus · Accepted Answer

The energy of the ground state of an electron in a one-dimensional box of width L is given by:E = (h^2 / 8mL^2) * n^2where h is Planck's constant, m is the mass of the electron, L is the width of the box, and n is the principal quantum number.In this case, L = 2 * 0.0529 nm = 0.1058 nm and n = 1 for the ground state.Plugging these values into the equation, we get:E = (6.626 * 10^-34 J s)^2 / (8 * 9.109 * 10^-31 kg * (0.1058 * 10^-9 m)^2) * 1^2= 5.38 * 10^-18 JTherefore, the correct answer is A.

Suppose an Electron Is Confined in a One-Dimensional Box of Width